Solution Essay Samples and Topic Ideas

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solution to the weeds they were going through;Oedipus sent Creon to consult the oracle and he knew how to say that the people will be released from the weeds when they find and punish the murderer of Layo and Oedipus committed to the people to find the culprit. Subsequently, Oedipus begins to ask about Layo's death and Creon tells him that Layo was killed when he ran into several thieves and that the only one who could escape was the pastor who accompanied them. Oedipus when investigating what happened with Layo, begins to speculate that he was the one who kill him. In an argument with the fortune tresias, the latter tells him that he is the criminal and that he must fulfill what he promised to the...

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Solution. tan-1x = arctan x at the interval (-π,2π,2) therefore the horizontal asymptote for 2 arctan x is y = ±π for y=2tan-1x(e) Asymptotes of f(x) =9x2+59x4+1dropping dominant terms we drop everything except big exponent f(x) =9x29x4=9x23x2=3Hence the horizontal asymptote equation is y=33). Consider f(x)=x2-2x+4x-2a). the domain. x<2b). the coordinates of the x-intercepts if y=0, x is not defined hence no solutions c). coordinates of the y-intercepts 0,-2d).the coordinates of the critical points (0,-2) and (4, 6) e). the intervals on which the function increases or decreases get the first derivative using the quotient rule (Chen, Fox & Lyndon 82)...

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Solution Given dl/dt=3 And dw/dt=-2 Then dp when l=12 ft and w=8ft Perimeter= 2l+2w Dp/dt=d/dt{2l+2w} =2dl/dt+2dw/dt=2(3)+2(-2) =2 ft/sec How fast is the area changing? Solution Given dl/dt=3, dw/dt=-2 Da/dt when l=12 ft , w=8ft Area=lxwDa/dt=d/dt{lxw} =Dl/dt*w+dw/dt*l =3(8)+ 12(-2) =0 ft2/sec (c) Find all critical points and local extremes of the following function on the given intervals. f (x) = 2-x3 on Solution To find the critical points, take derivative: f’(x)=-3x2 f’(X)= 0 0=-3x2 X=0 For absolute minima and maxima; f(0)=2-(0)3=2 f(-2)=2-(-2)3=10 f(1)=2-(1)3=1 Therefore: abs minima =1 at x=1 Abs maxima=10 at x=-2 (d) Calculate the limits of the...

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solution of by using the following steps (i) Find, where xn+1=xn- f(x)f'(x)f'x= 6x²+5x0 f(x)f'(x)xn+1=xn- f(x)f'(x)0-651.2x=1.2ii) Find, where xn+1=xn- f(x)f'(x)f'x= 6x²+5x0 f(x)f'(x)x0+1=x0- f(x)f'(x)11110.0909x=0.0909iii)x0 = 3 iv)Find, where xn+1=xn- f(x)f'(x)f'x= 6x²+5x0 f(x)f'(x)x0+1=x0-...

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Solution: 4x23y is the same as 4*√x23y= 2x3ySimplify the expression. Show your work. Solution: Opening the brackets; 3*1+3*5i-4i*1 -4i*5i-2-iCollecting like terms; 3+15i-4i-20i2-2-i3+11i-20i2-2+i 1+12i-20i2The formula represents the length of the hypotenuse of a right triangle with side lengths a and b. Solve the equation for b. Show your work. Solution: Finding the square of both sides gives: c2= a2+b2b2= c2- a2Now find the square roots in both sides. Therefore, b...

Solution: This is not a function there are two different pairs of the form (3,-) in f f = {(1, 2), (2, 3), (4, 2)} Solution: With the given domain, this is not a function since a pair of the form (3,-) does not exist. f = {(1, 1), (1,2), (1,3), (1,4)} Solution: This is not a function since more than one pair of the form (1,-) exists. e. f = {(1, 4), (2, 3), (3,2), (4,1)} Solution: This is function since the pairs of the (1,-) and (3,-) exists. Suppose A is the set of students currently registered at the University of Calgary, B is the set of professors at the University of Calgary, and C is the set of courses currently being offered at the University of Calgary. Under what conditions is each of the...

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