Since Essay Samples and Topic Ideas
since the high figures can also be an indication that the company is not making the best use of its working capital, has not secured financing and is not making efficient use of its current assets. In this respect, the current ratio results show that Potz and Pans is more likely to get the loan when compared to WannaBees. Question 2. The acid-test ratio for Potz and Pans has been calculated as 1.67:1 whereas the acid-test ratio for WannaBees has been calculated as 0.29:1. Based on the results, Potz and Pans should receive the loan. This is because the company has a ratio figure of 1.67:1 to indicate that for every $1 of current liability, the company has $1.67 liquid assets value to cover its...
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Since k3+5k=6p)…(i)In case k is an even number, then k=2x for some integer x. Substituting this value in equation (i) we have, 6p+1+3k2+3=6p+1+3(4x2)+3(2x)=6p+1+62x2+6x=6(p+2x2+x+1) Which is divisible by 6. Therefore, n3+5n is divisible by 6 for all n≥1Question 5 b. 13+2+…+n3=n2(n+1)24 For any natural number n. Proof Assuming that the equation is defined as Pn: 13+2+…+n3=n2(n+1)24 then when n=1 we have, 12(1+1)24=12224=1 Therefore, P1 is true. If we assume that Pk is also true, then we have 13+23+…+k3=k2(k+1)2413+23+…+k3+ k+13=k2k+124+k+13Factoring out k+12 the LHS becomes =k+12(k24+k+1)=k+12(14k2+4k+4)=k+12(k+2)24=k+1224It means that Pk holds true for Pk+1. Since P1 true and Pk→P(k+1)...
Since the approximating function is linear in value, it is easier to employ the matrix method to derive the weight coefficient. This type of the equation is applied where prediction of series is required as well as when controlling nonlinear systems that present unstable behaviors. Essentially, Radial Basis Functions are typically trained by a two-step algorithm. Akima Interpolation This is a continuously differentiable spline interpolation built from third order piecewise polynomials. In Akima interpolation, the interpolation polynomials are only determined by the data from the next neighbor points. This makes the method computationally very efficient and hence there is no need to solve the large...
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- Pages: 1
since a pair of the form (3,-) does not exist. f = {(1, 1), (1,2), (1,3), (1,4)} Solution: This is not a function since more than one pair of the form (1,-) exists. e. f = {(1, 4), (2, 3), (3,2), (4,1)} Solution: This is function since the pairs of the (1,-) and (3,-) exists. Suppose A is the set of students currently registered at the University of Calgary, B is the set of professors at the University of Calgary, and C is the set of courses currently being offered at the University of Calgary. Under what conditions is each of the following function? {(a, c) | a is taking a course from b} Solution: Not a function. Each student is taking courses handled by b1 and b2, then the sets have (a, b1) and (a,...
Since I will increase the number of words, I will also increase the time the first group takes to read the words from five minutes to fifteen minutes. Equally, I will increase the time the second group takes from seven minutes to twenty minutes. Increasing the two variables will help reduce the error of bias. The first group will be asked to read the first fifteen words. However, the words should be displayed on a big screen or board, and the words should appear one by one in intervals of one minute per word. The second group will also be asked to read the same words but the time interval between words will be increased to about 1.2 minutes. The second list of thirty words should then be displayed...